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#include <iostream.h>
class A
{int i;
public:
virtual void fun()=0;
A(int a)
{i=a;}
};
class B:public A
{int j;
public:
void fun()
{cout<<"B::fun()＼n"; }
B(int m,int n=0):A(m),j(n){}
};
void main()
{A *pa;
B b(7);
pa=&b;
}
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答案：B(int m,int n=0):A(m),j(n){}因为基类是抽象类，不能被实例化，所以在派生类中不能调用初始化基类对象。所以B(int m,int n=0):A(m),j(n){}错误，删去A(m)。［修改］B(int m,int n=0):j(n){}
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